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Question

An electron of energy 1800 eV describes a circular path in magnetic field of flux density 0.4 T. The radius of path is (q = 1.6 X 1019 C, me = 9.1 X 1031 kg)

A
2.58 X 104m
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B
3.58 X 104m
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C
2.58 X 103m
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D
3.58 X 103m
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Solution

The correct option is C 3.58 X 104m
E=12mv2v=2Em
r=mvBe=mBe2Em=2mEBe
r=2×1800×1.6×1019×9.1×10311.6×1019×0.4=3.58×104m

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