The force on the electron due to the electric field in,
F−eE. [Electrons have charge q=−e]
now, as F = ma, acceleration of electron :-
a=Fm=−eEm
initially electron was at rest (u = 0) so at a time 't' its velocity would be :-
v=u+at⇒v=−eEmt
Thus, at a time 't' its momentum would be,
p=mv=−eEt
and its de-Broglie wavelength :
λ=hp=−heEt
Thus rate of change of de-Broglie wavelength,
dλdt=heEt2 [ddt(1t)=−1t2]