An electron of mass $m$ and charge $e$ , is accelerated from rest through a potential difference $V$ in vacuum. Its final speed will be:

\sqrt{(e V / m)}

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2 e V / m

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\sqrt{(e V / 2 m)}

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\sqrt{(2 e V / m)}

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Solution

The correct option is B $\sqrt{(2 e V / m)}$
An electron of mass m and charge e, is accelerated from rest through a potential difference V in vacuum. Its final speed will be $\sqrt{(2 e V / m)}$
The kinetic energy $\frac{1}{2} m u^{2} = e V$
$u^{2} = \frac{2 e V}{m}$
$u = \sqrt{(2 e V / m)}$

Thus, option (D) is the correct answer.

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