An electron of mass $M k g$ and charge $e c o u l o m b$ travels from rest through a potential difference of $V v o l t$ . The final velocity of the electron is $(i n m / s)$ :

\frac{2 e V}{M}

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\frac{2 M V}{e}

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\sqrt{\frac{2 e V}{M}}

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\sqrt{\frac{2 M V}{e}}

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Solution

The correct option is C $\sqrt{\frac{2 e V}{M}}$
Energy gained by an electron $= q Δ V$
$= V \times e$
this energy is in the from kinetic energy
$\Rightarrow \frac{1}{2} M v_{f}^{2} = V \times e$
$\Rightarrow v_{f}^{2} = \frac{2 e V}{M}$

$\Rightarrow v_{f} = \sqrt{\frac{2 e V}{M}}$

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