An electron - positron pair is formed by a - -ray of 2 MeV- The K-E- imparted to each member of the pair if they share the K-E- equally is-

The correct option is C 0.488 MeV Now initially there is 2 MeV . (2 × 0.512 MeV) goes into the formation of the electron and proton #160;(rest ...

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Standard XII

Physics

Interstellar Alchemy

An electron -...

Question

An electron - positron pair is formed by a $γ$ -ray of $2 M e V$ . The K.E. imparted to each member of the pair if they share the K.E. equally is.

5.12 M e V

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0.512 M e V

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0.488 M e V

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0 M e V

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Solution

The correct option is C $0.488 M e V$
Now initially there is $2 M e V$ .
$(2 \times 0.512 M e V)$ goes into the formation of the electron and proton (rest masses).

What energy is left is $0.976 M e V$ which is equally shared and is their $K E$ .

i.e $2 K E = 0.976 M e V$
$⟶ K E = 0.488 M e V$

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An electron - positron pair is formed by a γ -ray of 2MeV. The K.E. imparted to each member of the pair if they share the K.E. equally is.

The correct option is C 0.488MeVNow initially there is 2 MeV.(2×0.512 MeV) goes into the formation of the electron and proton (rest masses).What energy is left is 0.976 MeV which is equally shared and is their KE.i.e 2KE=0.976 MeV⟶KE=0.488 MeV

An electron - positron pair is formed by a $γ$ -ray of $2 M e V$ . The K.E. imparted to each member of the pair if they share the K.E. equally is.

The correct option is C $0.488 M e V$
Now initially there is $2 M e V$ .
$(2 \times 0.512 M e V)$ goes into the formation of the electron and proton (rest masses).

What energy is left is $0.976 M e V$ which is equally shared and is their $K E$ .

i.e $2 K E = 0.976 M e V$
$⟶ K E = 0.488 M e V$