Question

An electron revolving around the nucleus in an orbit has angular momentum equal to$\frac{h}{27\pi }$. Can it lose energy?

Answer 1

Yes, it will lose energy, since the energy is quantized and the angular momentum in a certain orbit must be equal to $\frac{nh}{2\pi }(n=0,1,2,....)$ or $n$ should be integer value in order to not lose energy.

but $\frac{nh}{2\pi }=\frac{h}{27\pi }\Rightarrow n=\frac{2}{27}$ which is not an intger.