An electron starting from rest has a velocity that increases linearly with time,i.e. v=kt where $k = 2 m / s^{2}$ . The distance covered in the first three seconds will be

36m

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27m

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18m

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Solution

The correct option is D 9m
From the given information , v $= k t$
Acceleration of the body 'a' $= k = 2 m / s^{2}$
Using the equations of motion
$s = u t + \frac{1}{2} a t^{2}$
u = 0
$s = 2 \times (1 / 2) \times 3^{2}$
$s = 9 m$

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An electron starting from rest has a velocity that increases linearly with time,i.e. v=kt where k=2 m/s2. The distance covered in the first three seconds will be

The correct option is D 9mFrom the given information , v=ktAcceleration of the body 'a' =k=2m/s2Using the equations of motions=ut+12at2u = 0s=2×(1/2)×32s=9m

An electron starting from rest has a velocity that increases linearly with time,i.e. v=kt where $k = 2 m / s^{2}$ . The distance covered in the first three seconds will be

The correct option is D 9m
From the given information , v $= k t$
Acceleration of the body 'a' $= k = 2 m / s^{2}$
Using the equations of motion
$s = u t + \frac{1}{2} a t^{2}$
u = 0
$s = 2 \times (1 / 2) \times 3^{2}$
$s = 9 m$