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Question

An electron travelling with a velocity ¯V=107i m/s enter a magnetic field of induction ¯B=¯¯¯¯¯2j . The force on electron is

A
1.6×1012¯jN
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B
3.2×1012¯kN
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C
6.4×1012¯kN
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D
3.2×1012¯kN
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Solution

The correct option is B 3.2×1012¯kN
¯F=q(V×B)
=q×107×2ׯk
=1.6×1019×2×107¯kN
=3.2×1012¯kN

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