Question

An element A burns with golden flame in air. It reacts with another element B (atomic number 17) to give a product C. An aqueous solution of product C on electrolysis gives a compound D and liberates hydrogen. The elements and products involved is :

• A. Na
• B. NaCl
• C. NaOH
• D. All of these

Answer 1

Answer: (D)

All of these

Element A is sodium metal(Na) as it burns with a golden flame.
Element B with atomic number 17 is chlorine (Cl).
Sodium and chlorine combine to form sodium chloride, NaCl(compound C).

The reaction can be written as:

$2Na+C{l}_2\to 2NaCl$

Aqueous solution of NaCl on electrolysis gives the compound D, sodium hydroxide(NaOH). The equation for this can be written as:
$2NaCl\left(aq\right)+2H_{2}O\left(l\right)\to 2NaOH\left(aq\right)+C{l}_2\left(g\right)+H_2\left(g\right)$