An element A decay by a two step process into element C A - B - 2 H e 4 - B - C - 2 e -

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Standard XII

Physics

Nucleus: Common Terms

An element A ...

Question

An element A decay by a two step process into element C
$A \to B +_{2} H e^{4}$ $;$ $B \to C + 2 e^{-}$

A and B are isobars

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A and C are isobars

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A and B are isotopes

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A and C are isotopes

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Solution

The correct option is D A and C are isotopes

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Similar questions

Q. An element A decays into an element C by a two-step process:

A \to B + H e_{2}^{4}

and

B \to C + {2 e}_{- 1}^{0}

.Then

An element A decays into element C by a two step process:

$A \to B +_{2}^{4} H e$ ; $B \to 2 e^{-} + C$ Then

Q. An element

A

decays by a two-step process into element

C

A \to B + H e_{2}^{4}

B \to C + 2 e^{-}

Then-

Structures of nuclei of three atoms A, B, and C are given below: A has 90 protons and 146 neutrons. B has 92 protons and 146 neutrons. C has 90 protons and 148 neutrons. Based on the above data, which of these atoms are isotopes and which are isobars?

Q. An element

A

decays into element

C

by the following two step processes:

A ⟶ {_{2} H e}^{4} + B

B ⟶ 2 ({_{- 1} e}^{0}) + C

Select pair for isobars from elements

A, B

and

C

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An element A decay by a two step process into element CA→B+2He4 ; B→C+2e−

The correct option is D A and C are isotopes

An element A decay by a two step process into element C
$A \to B +_{2} H e^{4}$ $;$ $B \to C + 2 e^{-}$