Question

An element A has a valence electronic configuration $3s^{2}3p^5$ and the other element B has a valence electronic configuration $3s^1$. The bond formed between them is:

• A. Covalent
• B. Ionic
• C. Coordinate covalent
• D. Cannot predict

Answer 1

The correct option is B Ionic

From the valence electronic configuration, the element A is $Cl$ and the element B is $Na$. $Na$ is a metal and $Cl$ is a non metal. The bond formed between them will be ionic.
$Na$ loses one electron to attain a noble gas configuration $\left(Ne\right)$ and forms $N{a}^{+}$
$Cl$ gains one electron to attain a noble gas configuration $\left(Ar\right)$ and forms $C{l}^{-}$.
They form $NaCl$ which is an ionic compound.