An element A has two electrons in its fourth shell. State:
(a) It's atomic no
(b) Its electronic configuration
(c) Its valency
(d) Position in the periodic table
(e) Is it metal or non-metal
(f) Is it oxidizing or reducing agent
If metal A has two electrons in its fourth shell that means its electronic configuration will be 2, 8, 8, 2
So,
(a) Its atomic no. will be: 2+ 8+ 8+ 2 =20
(b) Its electronic configuration will be: 2, 8, 8, 2
(c) As we can see 2 electrons are there in its outer shell so it has to lose this two-electron to gain stability(the third shell has 8 electrons). So, 2 will be its valency.
(d) By electronic configuration it is clear that the last shell is the fourth shell so, period no. will be 4, and as two electrons are there in its outer shell so group no. will be 2nd.
(e) As it is clear by its configuration it has the capacity to lose 2 electrons and this is the property of metal so, it will be metal.
(f) As it has the capacity to release two electrons so it will act as a reducing agent.