An element 'A' has two electrons in the outermost shell of its atom and combines with an element 'B' having seven electrons in the outermost shell, forming the compound $A B_{2}$ . The compound when dissolved in water, conduct electric current. Giving reasons, state the nature of the chemical bond in the compound.

Open in App

Solution

Compound $A B_{2}$ . is ionic in nature.
Explanation: Atom A has two electrons in its outermost shell and atom B needs one electron to complete its octet. Atom A transfers its two electrons to two atoms of B (one electron to each atom B) and gets stabilised by forming ionic bonds.
When dissolved in water, the ions of this ionic compound get separated from each other and conduct electricity across the solution.

Suggest Corrections

Similar questions

Q. An atom of element A has three electrons in its outer shell and B has six electrons in its outermost shell. The formula of the compound formed between these two will be :

Q. An atom of one element A has three electrons in its outermost shell, and that of B has six electrons in the outermost orbit. The formula of the compound formed by these two will be :

An element A has 4 valence electrons in its atom whereas element B has only one valence electrons its atom. The compound formed by A and B does not conduct electricity. What is the nature of chemical bond in the compound formed ? Give its electron dot structure.

An atom X has 2,8,7 electrons in its shell. It combines with Y having 1 electron in its outermost shell.

(a) What type of bond will be formed between X and Y ?

(b) Write the formula of the compound formed.

Q. An atom

A

has

3

electrons in its outermost shell and another atom

B

has

7

electrons in its outermost shell. What is the correct formula for their compound?

Join BYJU'S Learning Program