Question

An element A is tetravalent and another element B is divalent. The formula of the compound formed from these elements will be:

• A. $A_{2}B$
• B. $AB$
• C. $A{B}_2$
• D. $A_2{B}_3$

Answer 1

The correct option is C $A{B}_2$

An element A is tetravalent hence oxidation number of $A$ can be $A^{+4}$

Element $B$ is divalent hence oxidation number of $B$ can be $B^{2-}$

According to the cris-cross method formula of the compound will be : $A_2{B}_4$ or $A{B}_2$

Hence, the correct option is $\text{C.}$