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Question

An element belongs to IIIA group and forth period in the modern periodic table. What could be the probable atomic number of that element?


A

23

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B

49

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C

31

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D

13

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Solution

The correct option is C

31


Explanation for Correct option:

C) The element that belongs to IIIA group and fourth period is Gallium(Ga).The first member of IIIA group is Boron(B) belongs to second period and its atomic number is 5. The next successive member will have 8 more protons in it and the next successive element will have 18 more protons.

So, 5+8+18 = 31 - Atomic number of the element in IIIA group and forth period.

Explanation for Incorrect options:

A) 23- is the atomic number of Vanadium(V) that belongs to forth period and VB group.

B) 49- is the atomic number of Indium(In) that belongs to forth period and VA group.

D) 13-is the atomic number of Aluminium(Al) that belongs to third period and IIIA group.

Hence, C) is the correct option - 31 - Atomic number of the element in IIIA group and forth period.


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