An element crystallises in face-centred cubic lattice with density as 5g/cm3 and edge length of the side of unit cell is 400 pm.
Take NA=6×1023 Then the molar mass of the element in gmol−1 is :
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Solution
Z=4 in fcc lattice ρ=5g/cm3 a=400pm=4×10−8cm ∴a3=64×10−24cm3 NA=6×1023 ρ=Z×MNA×a3