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Question

An element has 2 electrons in its shell .
i)Identify the element .
ii)What type of ion will it form ?
iii)What will be the formulae of its chloride ?
iv)Predict the solubility of its chloride .

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Solution

a) The element has 2 electrons in its valence shell. So it belongs to group II.Alkaline earth metal. b) The cation formed is of the type M2+ - cationc) The chlorides are of the formula MCl2d) The solubility of their chlorides increases on increasing the size.That means down the group metal chlorides are more soluble in water.BeCl2 is covalent and other chlorides of this group are ionic.

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