Question

An element has a bcc structure having the number of unit cells equal to $12.08\times {10}^{23}$. The number of atoms in these cells is:

• A. $12.08\times {10}^{23}$
• B. $24.16\times {10}^{23}$
• C. $48.38\times {10}^{23}$
• D. $12.08\times {10}^{22}$

Answer 1

The correct option is B $24.16\times {10}^{23}$

One unit cell of bcc has atoms $=2$
Hence, $12.08\times {10}^{23}$ unit cells will have atoms $=2\times 12.08\times {10}^{23}=24.16\times {10}^{23}$