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Byju's Answer
Standard XII
Chemistry
Tautomerism
An element ha...
Question
An element has a body centred cubic (bcc) structure with a cell edge of 288 pm. The atomic radius is
A
√
2
4
×
288
p
m
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B
4
√
3
×
288
p
m
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C
4
√
2
×
288
p
m
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D
√
3
4
×
288
p
m
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Solution
The correct option is
D
√
3
4
×
288
p
m
For BCC,
√
3
a
=
4
r
a = edge length
r = radius of atom
r
=
√
3
a
4
Given, a = 288 pm
r =
√
3
4
×
288
p
m
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