An element has atomic number 79. Predict the group and period in which the element is placed.

2nd group, 7th period

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11th group, 6th period

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13th group, 6th period

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12th group, 6th period

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Solution

The correct option is B 11th group, 6th period
The element with atomic number 79 is placed in 11th group and 6th period. The electronic configuration for $Z = 79$ is $[X e] 4 f^{14} 5 d^{10} 6 s^{1}$ (n = 6)
As $n = 6$ , the element belongs to 6th period.
Group number $=$ number of electrons in ns subshell $+$ number of electrons in (n -1)d subshell $= 1 + 10 = 11$ .
Note: For Xe, $Z = 54$

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