Question

An element has bcc structure having unit cells $12.08\times {10}^{23}$. Find the number of atoms in these cells.

Answer 1

There are two atoms in a bcc unit cell.

So, number of atoms in $12.08\times {10}^{23}$ unit cells =$2\times 12.08\times {10}^{23}$

= $24.16\times {10}^{23}$