Question

An element has cubic close packed structure. The distance between adjacent layers is $424.2$ pm. What would be the atomic radius of the element?

• A. $259.8$ pm
• B. $346.4$ pm
• C. $529.8$ pm
• D. $644.3$ pm

Answer 1

The correct option is A $259.8$ pm

Difference between layers $=\frac{a}{\sqrt{1^2+1^2+1^2}}=424.2$ pm$.$

$\therefore a=(424\cdot 2\times \sqrt{3})$ pm

and $4r=a\sqrt{2}$

$\therefore$ $r=\left(\frac{424\cdot 2\times \sqrt{3}}{4}\right)=259\cdot 8$ pm$.$