An element has nine positive charges in its nucleus. Its common oxidation state is:

+ 7

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+ 5

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- 1

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+ 1

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Solution

The correct option is B $- 1$
It means it has $9$ electrons.To get octet configuration it accepts one electron which comes into $2 p$ orbital hence oxidation state becomes $- 1$ .

Hence, the correct option is $C$

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