Question

An element having an atomic radius of 0.14 nm crystallizes in an FCC unit cell. What is the length of a side of the cell in nm
$(\sqrt{2}=1.4)$

Answer 1

For FCC unit cell, $\sqrt{2}a=4r$
Given, $r=0.14nm$
$\sqrt{2}a=4\times 0.14=0.56$
$a=\frac{0.56}{\sqrt{2}}$$=0.4nm$