An element is isobaric with the inert gas atom $_{18} A^{40}$ . The electronic arrangement of the element is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2}$ . How many neutrons does each atom of the element carry in its nucleus?

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Solution

The correct option is C 20
As given,
Atomic number of inert gas atom = 20
Atomic mass of inert gas atom = 40 (isobaric to $_{18} A r^{40}$ )
$∴$ Number of neutrons = 40 - 20 = 20

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An element is isobaric with the inert gas atom 18A40. The electronic arrangement of the element is 1s22s22p63s23p64s2. How many neutrons does each atom of the element carry in its nucleus?

The correct option is C 20As given,Atomic number of inert gas atom = 20Atomic mass of inert gas atom = 40 (isobaric to 18Ar40)∴ Number of neutrons = 40 - 20 = 20

An element is isobaric with the inert gas atom $_{18} A^{40}$ . The electronic arrangement of the element is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2}$ . How many neutrons does each atom of the element carry in its nucleus?

The correct option is C 20
As given,
Atomic number of inert gas atom = 20
Atomic mass of inert gas atom = 40 (isobaric to $_{18} A r^{40}$ )
$∴$ Number of neutrons = 40 - 20 = 20