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Question

An element with atomic number Z=11 emits Ka X-ray of wavelength λ, then the atomic number of the element which emits Ka. X-ray of wavelength 4λ is?

A
11
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B
44
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C
6
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D
5
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Solution

The correct option is B 6
According to Moseley's law
v=a(Zb)
Squaring both sides, v=a2(Zb)2
or cλ=a2(Zb)2
Therefore, for two different elements, the ratio of wavelengths is given by
λ1λ2=(Z21)2(Z11)2
Given : λ1=λ, Z1=11, λ2=4λ, Z2=?
λ4λ=(Z21)2(111)2;
or (Z21)2=25;
Z2=6.

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