wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An element with atomic number Z=11 emits KαX-ray of wavelength λ. The atomic number which emits KαX-ray of wavelength 4λ is

A
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
11
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
44
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 6
As per question,
given that atomic number of an element Z1=11
a wavelength of an elementλ1=λ
the atomic number of the second element Z2=?
a wavelenght of the second element λ2=4λ
According to Moseley's law v=a(zb)
or v=a2(zb)2
or cλ=a2(zb)2
λ1λ2=(z21)2(z11)2
λ4λ=(z21)2(111)2
or (z21)2=25 or z2=6
So the atomic number of the second elementZ2=6

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
de Broglie's Hypothesis
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon