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Standard X

Physics

Alpha Decay

An element ...

Question

An element $X$ decays first by positron emission and then 2 $α$ -particles are emitted in succession. If the product nucleus has mass number $229$ and atomic number $89$ , then the mass number and atomic number of element $X$ are

237, 93

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237, 94

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238, 93

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237, 92

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Solution

The correct option is D $237, 94$
$_{Z}^{A} X \to e^{+} + 2_{2}^{4} H e +_{89}^{229} X$
Mass balance, $A = 0 + 8 + 229$
$A = 237$
Charge balance, $Z = + 1 + 4 + 89$
$Z = 94$

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An element X decays first by positron emission and then 2 α-particles are emitted in succession. If the product nucleus has mass number 229 and atomic number 89, then the mass number and atomic number of element X are

The correct option is D 237,94AZX→e++242He+22989XMass balance, A=0+8+229 A=237Charge balance, Z=+1+4+89 Z=94

An element $X$ decays first by positron emission and then 2 $α$ -particles are emitted in succession. If the product nucleus has mass number $229$ and atomic number $89$ , then the mass number and atomic number of element $X$ are

The correct option is D $237, 94$
$_{Z}^{A} X \to e^{+} + 2_{2}^{4} H e +_{89}^{229} X$
Mass balance, $A = 0 + 8 + 229$
$A = 237$
Charge balance, $Z = + 1 + 4 + 89$
$Z = 94$