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Standard X

Physics

Alpha Decay

An element ...

Question

An element $X$ decays, first by positron emission and then two $α$ -particles are emitted in successive radioactive decay. If the product nuclei has a mass number $229$ and atomic number $89$ , the mass number and atomic number of element X are

237, 93

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237, 94

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221, 84

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237, 92

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Solution

The correct option is B $237, 94$
Given: $A - 8 = 224$ and $Z - 5 = 89$
$\Rightarrow A = 237, Z = 94$

$_{z} X^{A} \to_{z - 1} Y^{A} + e^{+} + V$
$↓$
$2 α +_{z - 5} X^{' A - 8}$

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An element X decays, first by positron emission and then two α-particles are emitted in successive radioactive decay. If the product nuclei has a mass number 229 and atomic number 89, the mass number and atomic number of element X are

The correct option is B 237,94Given: A−8=224 and Z−5=89 ⇒A=237,Z=94zXA→z−1YA+e++V ↓ 2α+z−5X′A−8

An element $X$ decays, first by positron emission and then two $α$ -particles are emitted in successive radioactive decay. If the product nuclei has a mass number $229$ and atomic number $89$ , the mass number and atomic number of element X are

The correct option is B $237, 94$
Given: $A - 8 = 224$ and $Z - 5 = 89$
$\Rightarrow A = 237, Z = 94$

$_{z} X^{A} \to_{z - 1} Y^{A} + e^{+} + V$
$↓$
$2 α +_{z - 5} X^{' A - 8}$