An element 'X' exhibits the maximum covalency of 7. Identify the ground state electronic configuration of 'X'?

3 s^{2} 3 p^{4}

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2 s^{2} 2 p^{5}

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3 s^{2} 3 p^{5}

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Both 2 and 3

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Solution

The correct option is B $3 s^{2} 3 p^{5}$
Covalency is the number of electron pairs an atom can share with other atoms. Therefore for an element 'X' that exhibits the maximum covalency of 7, the ground state electronic configuration can be written as; $3 s^{2} 3 p^{5}$

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