An element X has atomic number 19. What will be the formula of its oxide?

X_{2} O

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X O

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X O_{2}

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X_{2} O_{3}

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Solution

The correct option is A $X_{2} O$
Element X with atomic number 19 will lose one electron to form $X^{+}$ with 18 electrons corresponding to the stable noble gas electronic configuration.

Oxygen gains two electrons to form $O^{2 -}$ ion. One $O^{2 -}$ ion combines with two $X^{+}$ ions to form $X_{2} O$ .

Note: In a neutral molecule, the total charge on cations is numerically equal to total charge on anions.

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