X has mass number = 35 , no. of neutrons = 18
Atomic no. = Mass number - No. of neutrons
Atomic no. of X = 35 -18 = 17
Hence element X has atomic no. = 17
Electronic configuration = 2, 8, 7
Group number = 17 (10+ no. of valence electrons so 10+ 7 = 17)
Period number = no. of shells = 3
Valency = 1 as X will gain one electron to complete its octet.