An element ZMA emits one - alpha particle followed by two - beta particles- Among the following- the daughter element is -

A radioactive element $_{Z}^{A} X$ loses two successive $β - p a r t i c l e s$ and an $α - p a r t i c l e s$ such that resulting element is $_{Q}^{P} Y$ . Find the values of P and Q in terms of A and Z.

_{90} T h^{228}

emits four alpha and one beta particles. Number of neutrons in daughter element is :

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An element ZMA emits one α (alpha) particle followed by two β (beta) particles. Among the following, the daughter element is :

The correct option is C zMA−4ZMA→42He+2β+CDXMass balance, A=4+0+C C=A−4Charge balance, Z=2−2+D Z=D

An element $_{Z} M^{A}$ emits one $α$ (alpha) particle followed by two $β$ (beta) particles. Among the following, the daughter element is :

The correct option is C $_{z} M^{A - 4}$
$_{Z} M^{A} \to_{2}^{4} H e + 2 β +_{D}^{C} X$
Mass balance, $A = 4 + 0 + C$
$C = A - 4$
Charge balance, $Z = 2 - 2 + D$
$Z = D$