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Question

# An elevator ascends with an upward acceleration of 2 ms−2 . At the instant its upward speed is 2.5 ms−1, a loose bolt is dropped from the ceiling of the elevator 3m from the floor. (g=10ms−2 ). The time of flight of the bolt from the ceiling to floor approximately is

A
1s
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B
1.1s
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C
0.7s
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D
1.3s
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Solution

## The correct option is C 0.7sVelocity of bolt relative to elevator = 2.5 - 2.5 = 0 Acceleration of bolt relative to elevator a = 10 - (-2) = 12 ms−1 Using the relation, s=ut+12at2, we have 3.0=0×t+12×12t2⇒t=1√2s=0.7s

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