Question

An elevator has a mass of 4000 kg. When the tension in the supporting cable is 48000 N, What is the acceleration? Starting from rest, how far does it move in 3 s? $(g=10m/s^2)$

Answer 1

$F=ma$

upward acceleration is 'a'

F is tension

m is elevetor weight

$a=\frac{F}{m}$

$a=\frac{48000}{4000}$

$a=12m/s^2$

$v^2-u^2=2as$

S is height

$v=utat$

v = at ,u = 4

v = 36m/s

$v^2=2as$

S = 18m