CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 kg. The mass of the elevator itself is 920 kg and it moves with a constant speed 3 m/s. The frictional force opposing the motion is 6000 N. If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator (g=10m/s2) must be at least

A
62360 W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
56300 W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
48000 W
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
66000 W
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 66000 W
Step1: Draw a free body diagram of the given problem.

Step2: Find the tension in the cable of the elevator.

The elevator moving with constant speed hence

T=10mg+Mg+f

T=6800+9200+6000

T=22000 N

Step3: Find the power supplied by the motor.

Formula used: P=F.v

The power delivered by the motor to the elevator
Power =T.v

=22000×3

=66000 W

Final Answer: (c)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon