Question

An elevator, in which a man is standing, is moving upward with a constant acceleration of 1 m/ $s^2$. At some instant when speed of elevator is 10 m/s, the man drops a coin from a height of 2 m. Find the time taken by the coin the reach the floor. (g=9.8 m/$s^2$).

• A. 0.2s
• B. 0.61s
• C. 0.1s
• D. 0.4s

Answer 1

The correct option is B

0.61s

Use the equation for motion in one dimension,

t = $\sqrt{\frac{2\times 2}{10.8}}$ = 0.61 s