Question

An elevator is going up. the variation in the velocity of the elevator is as given in the graph. what is the height to which the elevator takes the passengers

• A. $3.6m$
• B. $28.8m$
• C. $36.0m$
• D. None of these

Answer 1

Answer: (C)

$36.0m$

The velocity time graph of the elevator is given, we know that the area under the curve on the time axis gives the displacement.

Height to which the elevator takes the passengers = Area of the trapezium

$\Rightarrow H=\frac{1}{2}\times \text{Sum of the parallel sides}\times \text{Distance between them}=\frac{1}{2}\times (12+8)\times 3.6=\frac{1}{2}\times 20\times 3.6=36m$