An elevator is moving upward with an acceleration $a$ it has velocity $v$ when a man inside the elevator lifts a body of mass $m$ through a height $h$ (in time $t$ ). The average power developed by the man is :

\frac{m (g + a) h}{t}

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m (g + a) (v + \frac{1}{2} a t)

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\frac{m g h}{t}

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m g (v + \frac{1}{2} a t)

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Solution

The correct option is D $\frac{m (g + a) h}{t}$
The power developed by the man = power required in the reference frame of the man = Force $\times$ velocity $= m (g + a) . (h / t)$

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An elevator is moving upward with an acceleration a it has velocity v when a man inside the elevator lifts a body of mass m through a height h (in time t). The average power developed by the man is :

The correct option is D m(g+a)htThe power developed by the man = power required in the reference frame of the man = Force × velocity =m(g+a).(h/t)

An elevator is moving upward with an acceleration $a$ it has velocity $v$ when a man inside the elevator lifts a body of mass $m$ through a height $h$ (in time $t$ ). The average power developed by the man is :

The correct option is D $\frac{m (g + a) h}{t}$
The power developed by the man = power required in the reference frame of the man = Force $\times$ velocity $= m (g + a) . (h / t)$