An elevator is moving vertically up with an acceleration $a$ the force exerted on the floor by a passenger of mass $m$ is:

m g

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m a

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m g - m a

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m g + m a

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Solution

The correct option is B $m g + m a$
$R =$ Normal reaction by the elevator floor on the passenger
$a =$ Acceleration of elevator upward
$m g =$ Weight of passenger
Using Newton's 2nd law,
$R - m g = m a$
$\Rightarrow R = m (g + a)$
Force by the passenger on the elevator floor is same as $R$ by Newton's 3rd law.

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An elevator is moving vertically up with an acceleration a the force exerted on the floor by a passenger of mass m is:

The correct option is B mg+maR= Normal reaction by the elevator floor on the passengera= Acceleration of elevator upwardmg= Weight of passengerUsing Newton's 2nd law,R−mg=ma⇒R=m(g+a)Force by the passenger on the elevator floor is same as R by Newton's 3rd law.

An elevator is moving vertically up with an acceleration $a$ the force exerted on the floor by a passenger of mass $m$ is: