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Instantaneous Force and Impulse

An elevator o...

Question

An elevator of mass $500$ kg is to be lifted up at a constant velocity of $0.4 m / s^{- 1}$ . What should be the minimum horse power of the motor to be used? ( Take g= $10 m s^{- 2}$ and $1 h p = 750$ watts).

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Solution

power = work done / time

$= \frac{m g D}{t}$

$= \frac{500 \times 10 \times 0.4}{1} = 2000 W$

$= 2.68 H P [1 w a t t = 0.00134 H P]$

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