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Question

An elevator which is moving with an upward acceleration of "a m/s2”. A person drops a coin to measure the acceleration 'a m/s2'. Find 'a' if the coin took 0.5s to hit the ground and the coin was dropped from a height of 3 m.

A

10 m/s2

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B

14 m/s2

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C

5 m/s2

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D

0 m/s2

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Solution

The correct option is B

14 m/s2


Ulift=+U
Ucoin=+U (same)

So ucoin/lift=UU=0
So with respect to lift coin's initial velocity=0
Now alift=+a
acoin=g
acoin/lift=ga

Now w.r.t. i.e., if I am the lift and I have eyes I will see the coin falling a fall of 3m. So the displacement will be -3 as in negative y-axis. Now, s=ut+12at2
3=0+12(ga)(12)2 ( since, t=0.5sec)

+3=(g+a)g
g+a=24
a=24-g=14 m/s2
So lift is going 14 m/s2 in upward direction.

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