An ellipse having foci at (3,1) and (1,1) passes through the point (1,3). Its eccentricity is:
A
√2−1
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B
√3−1
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C
12(√2−1)
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D
12(√3−1)
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Solution
The correct option is A√2−1 S≡(3,1),S′≡(1,1) and P≡(1,3) ⇒PS=√(3−1)2+(1−3)2=2√2,PS′=√(1−1)2+(1−3)2=2 Using definition of an ellipse PS+PS′=2a⇒a=√2+1 Also SS′=2ae=2⇒e=1a=1√2+1=√2−1