wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An ellipse passes through the points (3,1) & (2,2) & its principal axis are along the co-ordinate axes in order. Find its equation.

A
3x2+5y2=32
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5x2+3y2=32
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3x2+5y2=64
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5x2+3y2=64
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3x2+5y2=32
Let the ellipse be x2a2+y2b2=1
Given it passes through (3,1) and (2,2)
9a2+1b2=1 (i)
and 4a2+4b2=1 (ii)
Solving (i) and (ii) we get a2=323,b2=325
Hence the ellipse is, 3x2+5y2=32.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ellipse and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon