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Question

An ellipse passes through the points (3,1) & (2,2) & its principal axis are along the co-ordinate axes in order. Find its equation.

A
3x2+5y2=32
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B
5x2+3y2=32
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C
3x2+5y2=64
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D
5x2+3y2=64
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Solution

The correct option is B 3x2+5y2=32
Let the ellipse be x2a2+y2b2=1
Given it passes through (3,1) and (2,2)
9a2+1b2=1 (i)
and 4a2+4b2=1 (ii)
Solving (i) and (ii) we get a2=323,b2=325
Hence the ellipse is, 3x2+5y2=32.

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