An ellipse with centre at origin passes through the points (2,2),(1,4). Then the length of its major axis is
A
2√5
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B
3√5
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C
5√5
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D
4√5
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Solution
The correct option is B2√5 Let the equation of ellipse be x2a2+y2b2=1 Since, it passes through (2,2) and (1,4) then 4a2+4b2=1 ....(1) and 1a2+16b2=1 .....(2) Solving (1) and (2), simultaneously 1a2=15 Therefore, 2a=2√5