Question

An elliptical cavity is charge within perfect conductors. A positive charge $q$ is placed at the centre of the cavity. The points $A$ and $B$ are on the cavity surface as shown, Then:

• A. Electric field near $A$ in the cavity $=$ electric field near $B$ in the cavity.
• B. Charge density at $A=$ charge density at $B$.
• C. Potential at $A=$ potential at $B$.
• D. Total electric field flux through the surface of the cavity is $q/{\epsilon }_0$

Answer 1

Answer: (C), (D)

The correct options are
C Potential at $A=$ potential at $B$.
D Total electric field flux through the surface of the cavity is $q/{\epsilon }_0$