An emf induced in a secondary coil is 10000V when the current breaks in the primary. The mutual inductance is 5H and the current reaches to zero in 10−4 s in primary. The maximum current in the primary before the break is
A
0.2A
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B
0.3A
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C
0.4A
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D
0.5A
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Solution
The correct option is A0.2A ϕ=Mi emf=dϕdt=Mdidt 10000=5×i10−4 i=0.2A