An emf of 16V is induced in a coil having inductance 4H, if current in coil is 2A (at that moment), then the rate of change of energy stored in solenoid
A
30J/s
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B
32J/s
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C
64J/s
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D
8J/s
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Solution
The correct option is B32J/s Given, ε=16V,L=4H energy stored in solenoid ε=12Li2 On differentiate the above equcation, dεdt=Lididt→(Ldidt)i where, Ldidt=ε Hence, =16×2=32J/s