Question

An emf of 2V is induced in a coil when current in it is changed from 0A to 10A in 0.40 sec. Find the coefficient of self-inductance of the coil.

Answer 1

Let self-inductance of the coil be $L$, emf of the cell be $e$ and current in the circuit be $i$
$L=\frac{e}{di/dt}$
$=\frac{2}{10}\times 0.40$
$=0\cdot 08H$