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Self Induction

An emf of 2V ...

Question

An emf of 2V is induced in a coil when current in it is changed from 0A to 10A in 0.40 sec. Find the coefficient of self-inductance of the coil.

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Solution

Let self-inductance of the coil be $L$ , emf of the cell be $e$ and current in the circuit be $i$
$L = \frac{e}{d i / d t}$
$= \frac{2}{10} \times 0.40$
$= 0 \cdot 08 H$

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