An enantiomerically pure acid is treated with racemic mixture of an alcohol having chiral carbon, the ester formed will be:

mixture of diastereomers

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mixture of enantiomers

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meso compound

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racemic mixture

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Solution

The correct option is A mixture of diastereomers
A mixture of diastereomers is obtained with no optical rotation when we mix enantiomeric acid with an alcohol having chiral carbon.

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Pure enantiomeric acid + optically active alcohol having chiral C atom $\to$ ?

B r_{2}

C C l_{4}

F e B r_{3}

C

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